SOLUTION: two numbers different by 9,and the sum of their reciprocals is 5/12.find the numbers?
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Question 518930: two numbers different by 9,and the sum of their reciprocals is 5/12.find the numbers?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
x-y =9
x=y+9
1/x+1/y =5/12
substitute x
muktiply by y(y+9) the LCD
cross multiply
12(2y+9)=5(y(y+9))
24y+108=5y^2+45y
5y^2+21y-108=0
Find the roots of the equation by quadratic formula
a= 5 , b= 21 , c= -108
b^2-4ac= 441 + 2160
b^2-4ac= 2601
y1=( -21 + 51 )/ 10
y1= 3
y2=( -21 -51 ) / 10
y2= -7.2
12 & 3 is one of the solution.
-7.2 & 1.8
m.ananth@hotmail.ca
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