# SOLUTION: If the product of 2 consecutive integers is 45 more than 5 times the first integer. What are the 2 integers?

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 Question 510255: If the product of 2 consecutive integers is 45 more than 5 times the first integer. What are the 2 integers?Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!one integer be x other will be (x+1) x(x+1)=5x+45 x^2+x=5x+45 x^2-5x+x-45=0 x^2-4x-45=0 x^2-9x+5x-45=0 x(x-9)+5(x-9)=0 (x-9)(x+5)=0 x=9 OR -5 The integers are (9,10) , (-5,-4)