SOLUTION: Find three consecutive even integers such that the sum of five times the first, six times the second and seven times the third is 148

Question 508963: Find three consecutive even integers such that the sum of five times the first, six times the second and seven times the third is 148
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Let
1st Interger = x+2
2nd Integer = x+4
3rd Integer = x+6
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Given
5(x+2)+6(x+4)+7(x+6)=148
5x+10+6x+24+7x+42=148
18x+76=148
18x=148-76
18x=72
18x/18=72/18
x=4
--------------------------------------
1st Integer = x+2 =4+2=6
2nd Integer = x+4 = 4+4=8
3rd Integer = x+6 = 4+6=10
---------------------------------------
Check
(5*6)+6*(8)+7*(10)=148
30+48+70=148
148=148

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