SOLUTION: Find two consecutive integers such that the sum of the smaller and twice the greater is 32

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Question 506371: Find two consecutive integers such that the sum of the smaller and twice the greater is 32
Answer by Maths68(1474) About Me  (Show Source):
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Let
Smaller integers = x
Greater = x+1
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Given
x+2(x+1)=32
x+2x+2=32
3x=32-2
3x=30
x=30/3
x=10
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Smaller integer = x = 10
Greater integer = x+1 = 10+1=11
=================================================
Check
x+2(x+1)=32
10+2(10+1)=32
10+2(11)=32
10+22=32
32=32