SOLUTION: the sum of 4 consecutive odd integers is 432. What are the numbers?

Question 500740: the sum of 4 consecutive odd integers is 432. What are the numbers?
Found 2 solutions by Alan3354, oberobic:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
432/4 = 108, the center
--> 105, 107, 109 & 111

Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
x = first integer
x+2 = second consecutive odd number
x+4 = third
x+6 = fourth
.
x +x+2 + x+4 +x+6 = 432
4x +12 = 432
4x = 420
x = 105
.
So, the four consecutive odd integers are: 105, 107, 109, and 111.
.
Always check your work.
105+107+109+111 = ??
= 432
Correct.
.
Done.
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