SOLUTION: find three consecutive odd integers such that three times the sum of the first two integers is ten more than the product of the third integer and four.

Question 494849: find three consecutive odd integers such that three times the sum of the first two integers is ten more than the product of the third integer and four.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
"three consecutive odd integers"
x, (x+2), (x+4)
:
"three times the sum of the first two integers is ten more than the product of the third integer and four."
3(x + (x+2)) = 4(x+4) + 10
3(2x + 2) = 4x + 16 + 10
6x + 6 = 4x + 26
6x - 4x = 26 - 6
2x = 20
x = 20/2
x = 10
:
10, 12, 14, these are not odd but the only integers that satisfy the given statement
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