SOLUTION: Find three consecutive intergers such that the sum of the second and third excedds half of the first by 33

Question 493824: Find three consecutive intergers such that the sum of the second and third excedds half of the first by 33
Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
Let x be the first integer.
Then x + (x+1) + (x+2) are three consecutive integers.
We know that the sum of the second (x+1) and the third (x+2) is (x+33)/2
So
Combine and simplify

Subtract 33 on both sides.

Multiply by 2 on both sides

Combine like terms.

Divide by -3

So the consecutive integers are 20,21,22.

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