SOLUTION: The product of two consecutive positive even integers is 360. Find the integers. Thanks

Question 48351: The product of two consecutive positive even integers is 360. Find the integers.

Thanks
Found 3 solutions by venugopalramana, stanbon, Nate:
Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!
The product of two consecutive positive even integers is 360. Find the integers.
LET ANY EVEN INTEGER=2N...NEXT EVEN INTEGER =2N+2
2N(2N+2)=360
N(N+1)=90
N^2+N-90=0
(N+10)(N-9)=0
N=9
THE 2 EVEN INTEGERS ARE 2*9=18 AND 20
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
1st even number : 2x
2nd even number : 2x+2
EQUATION:
Product = 360
2x(2x+2)=360
x(x+1) = 90
x^2+x-90=0
(x+10)(x-9)= 0
x=-10 or x=9
But 2x must be positive,so
1st even number: 2x=18
2nd eve number : 2x+2 = 20
Cheers,
Stan H.
Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!
First Number: i
Second Number: i + 2

i = 18 or i = -20 Remember: Positive
18 and 20

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1444 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 18, -20. Here's your graph:

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