SOLUTION: Find three consecutive odd integers such that three times the first integer is one less than the sum of the second and third integers

SOLUTION: Find three consecutive odd integers such that three times the first integer is one less than the sum of the second and third integers

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Question 468394: Find three consecutive odd integers such that three times the first integer is one less than the sum of the second and third integers
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
3(n)+1=(n+2)+(n+4)
3n+1=2n+6
n=5
n+2=7
n+4=9
The numbers are 5, 7, and 9..
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