Hi,

Let x,(x+1) and (x+2) represent the 3 consecutive integers 

Question states***

x(x+1)(x+2)= 120

x{x^2+3x+2) = 120

 x^3 + 3x^2 +2x - 120 = 0  |x = 4 a solution  64+48 + 8 -120 = 0

Integers are 4,5,6

CHECKING our Answer***

 4*5*6 = 120 

Answer by DJ02124(1)   (Show Source): You can put this solution on YOUR website!
 x

x+1

X+2

----------

x+x+1+x+2=120

3x+3=120

3x=117

x=39

------------

x=39

x+1=40

x+2=41

-------------

Check

39+40+41=120 

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