SOLUTION: 1. Find three consecutive even integers such that the sum of twice the second and half the first is 141 less than five times the third. 2. The sum of three numbers is 158. The

Question 464274: 1. Find three consecutive even integers such that the sum of twice the second and half the first is 141 less than five times the third.
2. The sum of three numbers is 158. The largest number is three more than the second number, and the smallest number is four less than the second number. Find the numbers. ( 8 points)
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
1. Let the first number be 2x, the second 2x+2, and the third 2x+4. We write the equation as we read:
, solving this equation we get:x=25.
Thus, the first number is 2*25=50, the second 2*25+2=52, and the third 2*25+4=54.
2. Let the second number be x, then the largest number is x+3, and the smallest
number is x-4. Write the equation as we read: x-4+x+x+3=158, solving this equation we get x=53. The largest number is 53+3=56, and the smallest number is
53-4=49.
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