SOLUTION: What are three consecutive odd integers so that five times the middle integer is nine more than twice the sum of the first and third integers?
Algebra.Com
Question 445726: What are three consecutive odd integers so that five times the middle integer is nine more than twice the sum of the first and third integers?
Answer by rwm(914) (Show Source): You can put this solution on YOUR website!
x
x+2
x+4
5*(x+2)=9+2*(x+x+4)
5x+10=9+2*(2x+4)
5x+1=4x+8
x=7
7, 9 and 11
check
5*(9)=9+2*(7+11)
45=9+2*18
45=9+36
45=45
ok
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