SOLUTION: the product of the second and third of three consecutive integers is 2 more than 7 times the first integer

Question 433620: the product of the second and third of three consecutive integers is 2 more than 7 times the first integer
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Let's have x be the first integer and x+1 and x+2 be the next 2 integers. Now we can set up the equation as:
(x+1)(x+2)=7x+2
Expand this out:
x^2+3x+2=7x+2
Subtract 7x and 2 to get:
x^2-4x=0
factor this out to get:
x(x-4)=0
Solve for x and we get:
x=0
x=4
So we can see that 0,1,2 and
4,5,6 work as answers.
Make sense?
RJ
www.math-unlock.com
RELATED QUESTIONS
the product of the second and third of three consecutive integers is 2 more than 10 times (answered by Fombitz,checkley79)

The product of the second and third of three consecutive integers is 2 more than 16 times (answered by mananth,MathTherapy)

Find three consecutive odd integers such that the product of the second and the third... (answered by ikleyn)

The product of the first and third of three consecutive integers is 3 more than 3 times... (answered by swincher4391)

The product of the first and third of three consecutive integers is 3 more than 3 times... (answered by jsmallt9)

The product of the first and third of three negative consecutive integers is 59 more than (answered by ikleyn,mananth,Edwin McCravy)

The product of the second and third of three consecutive integers is 2 more than 12 times (answered by Theo)

Find three consecutive positive even integers such that the product of the second and... (answered by dabanfield)

Find three consecutive positive even integers such that the product of the second and... (answered by solver91311)