Hi

Let x and (x+2)represent the two consecutive odd integers

Question states***

 x^2 - (x+2) = 28

 x^2 -x -30 = 0

factoring

(x-6)(x+5) = 0

(x-6)= 0    x = 6  |Toss out this solution as it is not an odd number

(x+5) =0    x = -5   the two consecutive odd integers are -5,-3

 

CHECKING our Answer***

  25 -(-3) = 28 

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