SOLUTION: what is twice the first of three consecutive even integers is ten more than the third. find the integers.

Question 430667: what is twice the first of three consecutive even integers is ten more than the third. find the integers.
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
Three consecutive integers could be called x, y and z. But that would make the solution too hard. Instead, then can be called x, x+2, and x+4. Now you have only the unknown x to solve.
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You're also told there is a relationship between the three numbers. Specifically, twice the first number (that is, 2x) is 10 more than the third number (2x = (x+4) + 10).
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2x = x + 14
Subtract x from both sides
x = 14
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That suggests the there consecutive even numbers are
x = 14
x+2 = 16
x+4 = 18
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Always check your work.
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2x = 2*14 = 28
Is that 10 more than the third number?
Yes, it is.
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Answer: The three consecutive integers are 14, 16, and 18.
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Done.
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