SOLUTION: Find two consecutive odd intergers such that 5 times the first interger is 12 more than 3 times the second.

Question 417987: Find two consecutive odd intergers such that 5 times the first interger is 12 more than 3 times the second.
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"Find two consecutive odd intergers such that 5 times the first interger is 12 more than 3 times the second."

x = first consecutive odd integer
x + 2 = second consecutive odd integer

5x = 3(x + 2) + 12 {five times 1st is twelve more than three times 2nd}
5x = 3x + 6 + 12 {used distributive property}
5x = 3x + 18 {combined like terms}
2x = 18 {subtracted 3x from both sides}
x = 9 {divided both sides by 2}
x + 2 = 11 {substituted 9, in for x, into x + 2}

9 and 11 are the two consecutive odd integers
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