SOLUTION: Word Problem: is actually a Problem with Consecutive odd positive integers Find three consecutive odd positive integers such that 2 times the sum of all three is 153 less than t

Question 415110: Word Problem: is actually a Problem with Consecutive odd positive integers
Find three consecutive odd positive integers such that 2 times the sum of all three is 153 less than the product of the first and second integers.
Here is what I have so far:
First Int: x
Second Int: (x+2)
Third Int: (x+4)
2(x+x+2+x+4)= 6x+32
6x+32= x(x+2)-153

0= x^2+2x-153
0= x^2-4x-185 Here is were I am lost (only 5 times 37 =185
and 1 times 185 = 185...How can I get -4?)
0= (x ? )(x ? )

Answer by sudhanshu_kmr(1152) (Show Source): You can put this solution on YOUR website!

2(x+x+2+x+4) = 6x +12
6x+12 = x(x+2) -153
=> 6x + 12 = x^2 +2x -153
=> x^2 +2x-6x -153-12 = 0
=> x^2 - 4x - 165 = 0
=> x^2 -15 x + 11 x -165 =0
=> x(x-15) +11(x -15) = 0
=> (x+11) (x-15) =0
so, x = 15
nubers are 15,17,and 19.

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