SOLUTION: Find three consecutive integers such that the sum of the first and second is 9 more than half of the third.

Algebra.Com
Question 408369: Find three consecutive integers such that the sum of the first and second is 9 more than half of the third.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Find three consecutive integers
Let x, (x+1), (x+2) represent the three consecutive integers respectively
Question states***
x + (x+1) = (x+2)/2 + 9
Solving for x
2x + 1 - x/2 = 1 + 9
(3/2)x = 9
x = 6 The three consecutive integers are 6,7,8

CHECKING our Answer***
6+7 = 4 + 9
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