SOLUTION: find two consecutive intergers such that twice the first is 26 more than the second

SOLUTION: find two consecutive intergers such that twice the first is 26 more than the second

Algebra.Com

Question 405302: find two consecutive intergers such that twice the first is 26 more than the second
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find two consecutive integers such that
twice the first is 26 more than the second
----
1st: x
2nd: x+1
----
Equation:
2x = (x+1)+26
---
2x = x + 27
x = 27 (1st)
x+1 = 28 (2nd)
===================
Cheers,
Stan H.
===========

RELATED QUESTIONS
find two consecutive integers such that twice the first is 26 more than the second (answered by kevwill)

Find three consecutive odd intergers such that the sum of the first and twice the third... (answered by fractalier)

Find two consecutive odd intergers such that 5 times the first interger is 12 more than 3 (answered by algebrahouse.com)

find two consecutive odd intergers such that twice the larger is 17 more than the... (answered by checkley71)

Find two consecutive odd intergers such that twice the larger is 17 more than the... (answered by stanbon)

Find three consecutive positive intergers such that the product of the first and second... (answered by htmentor)

find three consecutive odd intergers such that twice the sumof the first and third more... (answered by algebrahouse.com)

find three consecutive intergers such that the sum of twice the first and 4 times the... (answered by checkley77)

Find two consecutive intergers such that twice the first interger plus the second... (answered by checkley75,rmromero)