SOLUTION: The sum of three integers is 52. The second integer is 3 more than the first. The third integer is 1 more than twice the first. What are the integers?

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The sum of three integers is 52. The second integer is 3 more than the first. The third integer is 1 more than twice the first. What are the integers?      Log On


   

Question 401199: The sum of three integers is 52. The second integer is 3 more than the first. The third integer is 1 more than twice the first. What are the integers?
Found 2 solutions by sofiyac, Tatiana_Stebko:
Answer by sofiyac(983) About Me  (Show Source):
You can put this solution on YOUR website!
let the first integer be x
then the second will be x+3
then the third one will be 2x+1
Now you can add them up and make sum equal to 52
x+x+3+2x+1=52
4x+4=52
4x=48
x=12
so since we named the first one x, then the first one is 12
then the second one is 12+3=15
then the third one is 2*12+1=25
:0)

Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
If the first integer is x
The second integer is 3 more than the first, then the second integer is %28x%2B3%29
The third integer is 1 more than twice the first, twice the first is 2x, then the thitd integer is %282x%2B1%29
The sum of three integers is x%2B%28x%2B3%29%2B%282x%2B1%29
From text the sum of three integers is 52
equation
x%2B%28x%2B3%29%2B%282x%2B1%29=52
x%2Bx%2B3%2B2x%2B1=52
4x=52-1-3
4x=48
x=48%2F4
x=12 the first integer
then the second is %28x%2B3%29=12%2B3=15
the third integer is %282x%2B1%29=2%2A12%2B1=25
Answer: 12; 15; 25