SOLUTION: Find three consecutive odd integers such that the sum of twice the first, twice the second, and three times the third is 9. An explanation would be great too!

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Question 398132: Find three consecutive odd integers such that the sum of twice the first, twice the second, and three times the third is 9. An explanation would be great too!
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

consecutive odd integers differ by two

Let x, (x+2),(x+4) represent the  three consecutive odd integers

Question states***Write as we Read

 2x + 2(x+2) + 3(x+4) = 9

solving for x

 2x + 2x+4 + 3x+12 = 9

      7x + 16 = 9

      7x = -7

       x = -1   the  three consecutive odd integers are: -1, 1, 3



CHECKING our Answer***

  -2 + 2 + 9 = 9

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive odd integers such that the sum of twice the first, twice the second, and three times the third is 9.
---
Odd numbers must be represented as an odd # more than or less than
an even number.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
2(2x-1)+2(2x+1)+3(2x+3) = 9
4x-2+4x+2+6x+9 = 9
14x + 9 = 9
14x = 0
x = 0
---
1st: -1
2nd: +1
3rd: 3
---
Check:
2(-1)+2(1)+3(3) = 9
checks
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Cheers,
Stan H.