SOLUTION: Find three consecutive positive even integers such that the product of the second and third integers is twenty more then ten times the first integer.

Algebra.Com
Question 397738: Find three consecutive positive even integers such that the product of the second and third integers is twenty more then ten times the first integer.
Answer by richard1234(7193)   (Show Source): You can put this solution on YOUR website!
Let x, x+2, x+4 be the integers, where x is even. Then,









x = 6, -2

Checking, both of these satisfy, but the question looks for positive even integers. So {6, 8, 10} are the three integers.

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