SOLUTION: If the product of two consecutive odd integers is 7 more than their some, what are the integers? x = one number x + 2 = the other number x(x + 2) = x + x + 2 + 7 x^2 + 2x

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: If the product of two consecutive odd integers is 7 more than their some, what are the integers? x = one number x + 2 = the other number x(x + 2) = x + x + 2 + 7 x^2 + 2x      Log On