SOLUTION: If the product of two consecutive odd integers is 7 more than their some, what are the integers?
x = one number
x + 2 = the other number
x(x + 2) = x + x + 2 + 7
x^2 + 2x
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Question 396749: If the product of two consecutive odd integers is 7 more than their some, what are the integers?
x = one number
x + 2 = the other number
x(x + 2) = x + x + 2 + 7
x^2 + 2x = 2x + 9
I am missing something....
Answer by MathLover1(20855) (Show Source): You can put this solution on YOUR website!
= one number
= the other number
I am missing something....just continue
...add } to the both sides
=+-
so, your numbers are:
3,5.....first solution
and
-3, -1........second solution
check both:
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