SOLUTION: find three consecutive integers such that the product of -5 and the sum of the first two is 43 less than twice the second.

Algebra.Com
Question 394707: find three consecutive integers such that the product of -5 and the sum of the first two is 43 less than twice the second.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Let x, (x+1), (x+2) represent the three consecutive integers
Write as we Read***
-5[ x + (x+1)] = 2(x+1) -43
solving for x
-10x - 5 = 2x - 41
36 = 12x
3 = x The three consecutive integers are 3,4,5
CHECKING our Answer***
-5*7 = 2*4 - 43 = -35
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