SOLUTION: What is the sum of two numbers that is -14, with their product at 48? I let x = one number and -14-x = the other number. Therefore, x(-14-x) = 48, -x^2 - 14x - 48 ?????

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Question 392675: What is the sum of two numbers that is -14, with their product at 48?
I let x = one number and -14-x = the other number. Therefore, x(-14-x) = 48,
-x^2 - 14x - 48 ?????
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
What is the sum of two numbers that is -14, with their product at 48?
The answer to your question is that it's an algebra problem.
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You should say "the sum of two numbers that is -14, with their product at 48?find the 2 numbers"
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I let x = one number and -14-x = the other number. Therefore, x(-14-x) = 48,
-x^2 - 14x - 48 ?
You had the right idea, but lost the equal sign.
-x^2 - 14x = 48 is better

(x+6)(x+8) = 0
x = -6, -8
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And, yes, I can be pedantic.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi

sum of two numbers that is -14

Let x and (-14 -x) represent tthe two numbers

Question states

 x(-14-x) = 48  

 -14x - x^2 - 48 = 0   |good work to thus far! 

x^2 +14x + 48 = 0

factoring

(x+6)(x+8)=0

(x+6)=0

 x = -6   Numbers are -6,-8   (-14-(-6) = -8)

(x+8)=0

 x = -8 yields the same results.  Numbers are -8, -6 

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