SOLUTION: find four consecutive even integers such that the sum of twice the first, five times the second, and four times the third divided by three times the fourth equals three

Question 390638: find four consecutive even integers such that the sum of twice the first, five times the second, and four times the third divided by three times the fourth equals three
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
Let x, x+2, x+4, x+6 be the 4 even integers.
[2x+5(x+2)+4(x+4)]/3(x+6)=3
[2x+5x+10+4x+16]/(3x+18)=3
[11x+26]/(3x+18)=3 cross multiply
11x+26=3(3x+18
11x+26=9x+54
11x-9x=54-26
2x=28
x=28/2
x=14 ans. for the first integer.
Proof:
[2*14+5(14+2)+4(14+4)]/3(14+6)=3
[28+5*16+4*18]/3*20=3
[28+80+72]/60=3
180/60=3
3=3

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