SOLUTION: 1) find three positive consecutive odd integers such that the largest decreased by twice the second is equal to 10 less than the smallest. 2) find three consecutive even integers

Question 390571: 1) find three positive consecutive odd integers such that the largest decreased by twice the second is equal to 10 less than the smallest.
2) find three consecutive even integers such that twice the sum of the first and second is 10 more than three times the third.
3) find three consecutive odd integers such that twice the sum of the second and third is 43 more than three times the first.
4) find four consecutive odd integers such that the sum of the first three exceeds twice the fourth by 5.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1) find three positive consecutive odd integers such that the largest decreased by twice the second is equal to 10 less than the smallest.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
2x+3 - 2(2x+1) = 2x-1-10
2x+3-4x-2 = 2x-11
-4x= -12
x = 3
1st: 2x-1 = 5
2nd: 2x+1 = 7
3rd: 2x+3 = 9
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2) find three consecutive even integers such that twice the sum of the first and second is 10 more than three times the third.
1st: 2x-2
2nd: 2x
3rd: 2x+2
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Equation:
2[2x-2+2x] = 3(2x+2)+10
2(4x-2) = 6x+16
8x-4 = 6x+16
2x = 20
x = 10
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1st: 2x-2 = 18
2nd: 20
3rd: 22
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Use the same procedure to solve the following two problems.
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Cheers,
Stan H.
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3) find three consecutive odd integers such that twice the sum of the second and third is 43 more than three times the first.
4) find four consecutive odd integers such that the sum of the first three exceeds twice the fourth by 5.
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