Hi,
Let x, (x+1),(x+2) represent the 1st, 2nd and 3rd consecutive integers(differ by 1),
for ex, then proceeding to Write as we Read
the sum of the first two equals three times the third.
1. x + (x+1) = 3(x+2)
three times the second equals 5 more than the first
2. (2 consecutive integers) 3(x+1) = x +5
sum of all 3 integers equals twice the 2nd
5. x + (x+1) + (x+2)= 2(x+1)
Odd or even consecutive integers differ by 2
Let x, (x+2), (x+4), (x+6) etc ... represent them in order
for ex, then proceeding to Write as we Read
sum of the second and the third equals 3 less than the first
3. (x+2) + (x+4) = x -3
sum of the 3rd and the 4th equals 6 less than 4x the second
4. (x+4) + (x+6) = 4(x+2)-6
solving for x in ease case, will result in naming the integers
1. x + (x+1) = 3(x+2)
2x + 1 = 3x + 6
-5 = x Integers are -5,-4,-3
2. 3(x+1) = x+5
3x + 3 = x + 5
2x = 2
x = 1 Integers are 1,2,3
Will leave the rest to for You. Always recommend checking your answers.