SOLUTION: Find three consecutive odd integers such that five times the middle integer equals 33 more than the sum of the first and the last.

Algebra.Com
Question 381611: Find three consecutive odd integers such that five times the middle integer equals 33 more than the sum of the first and the last.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
Let x, (x+2) and (x+4) represent the three consecutive odd integers
Write as we Read***
5(x+2) = x + (x+4) + 33
solving for x
5x + 10 = 2x + 37
3x = 27
x = 9
the three consecutive odd integers are 9, 11, 13
CHECKING our Answer***
45 = 9 + 13 + 33

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