SOLUTION: FIND FOUR CONSECUTIVE EVEN INTEGERS SO THAT THE SOME OF THE FIRST THREE IS TO MORE THAN THAT TWISE THE FOURTH

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Question 381474: FIND FOUR CONSECUTIVE EVEN INTEGERS SO THAT THE SOME OF THE FIRST THREE IS TO MORE THAN THAT TWISE THE FOURTH
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Let x, (x+2), (x+4) and (x+6) represent the FOUR CONSECUTIVE EVEN INTEGERS
Wrte as we Read
x + (x+2) + (x+4) = 2(x+6) + 2
solving for x
3x + 6 = 2x + 12 + 2
x = 8 8,10,12,14 are FOUR CONSECUTIVE EVEN INTEGERS
CHECKING our Anwer
8 + 10 + 12 = 30 = 2*14 + 2
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