SOLUTION: the product of the second and third of three consecutive integers is 2 more than 10 times the first integer?

Question 381447: the product of the second and third of three consecutive integers is 2 more than 10 times the first integer?

Found 2 solutions by Fombitz, checkley79:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
, , and are the three consecutive integers.

Two solutions:
, then the three integers are 0,1,and 2.
.
.
.

, then the three integers are 7, 8, and 9.

Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
LET X, X+1 & X+2 BE THE 3 INTEGERS.
(X+1)(X+2)=10X+2
X^2+3X+2=10X+2
X^2+3X-10X+2-2=0
X^2-7X=0
X(X-7)=0
X-7=0
X=7 ANS.
PROOF:
(7+1)(7+2)=10*7+2
8*9=70+2
72=72
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