Hi,

Let x represent the smallest of the three consecutive integers

then (x+1) and (x+2) would be the next two consecutive integers

Write as we Read

[x + (x+1)]^2 = (x+2)^2 +105

solving for x

[2x + 1)]^2 = (x+2)^2 + 105

4x^2 + 4x + 1 = x^2 + 4x + 4 +105

3x^2 - 108 = 0

x^2 = 108/3

x^2 = 36

x = +- 6

three consecutive integers are 6,7,8  Or -6,-5,-4 

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