SOLUTION: Find two consecutive odd integers such that twice the larger is 17 more than the smaller.

SOLUTION: Find two consecutive odd integers such that twice the larger is 17 more than the smaller.

Algebra.Com

Question 372518: Find two consecutive odd integers such that twice the larger is 17 more than the smaller.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the odd integers be x & x+2
..
twice the larger = 2(x+2)
17 more than the smaller
= x+17
..
2(x+2) = x+17
2x+4 =x+17
2x-x= 17-4
x= 13
13, 15 are the integers
..
m.ananth@hotmail.ca
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