SOLUTION: find three consecutive odd integers such that three times the first is 9 greater than six times the third

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Question 367893: find three consecutive odd integers such that three times the first is 9 greater than six times the third
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
Let x represent the smallest of the three consecutive odd integers.
The next two consecutive odd integers would be (x+2) and (x+4)
Write as we Read***
3x = 6(x+4) + 9
solve for x
3x = 6x + 24 + 9
-33 = 3x
-11 =x
the three consecutive odd integers are -11, -9 and -7
checking our answer
3*-11 = -33 = 6*-7 + 9
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