SOLUTION: Three times the sum of three consecutive integers x, x + 1, and x + 2, is 72. What are the integers?
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Question 367532: Three times the sum of three consecutive integers x, x + 1, and x + 2, is 72. What are the integers?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
3(x+x+1+x+2)=72
3(3x+3)=72
9x+9=72
9x=72-9
9x=63
/9
x= 7
..
mananth@hotmail.ca
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