SOLUTION: Find three consecutive odd integers such that the sum of the first and twice the second is 6 more than the third.

SOLUTION: Find three consecutive odd integers such that the sum of the first and twice the second is 6 more than the third.

Algebra.Com

Question 362833: Find three consecutive odd integers such that the sum of the first and twice the second is 6 more than the third.
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Let x, x+2, and x+4 be the 3 consecutive odd integers. Then x + 2(x+2) = (x+4) +6. Then x+2x+4 = x+10, or 3x + 4 = x+10, or 2x = 6, or x = 3. The 3 odd integers are 3,5,7.
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