SOLUTION: find three consecutive odd integers such that 3 times their sum is 5 more than 8 times the middle one

Question 351105: find three consecutive odd integers such that 3 times their sum is 5 more than 8 times the middle one
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
HI,
*Note: Consective Integers differ by one.
Let x represent the smallest, the (x+1) and(x+2) are the other two integers.
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Question States:
Write as You Read
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3(x + (x+1)+(x+2)) = 8(x+1) +5
3(3x+3)= 8x + 8 + 5
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simplify and solve
9x +9 = 8x + 13
x = 4
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(x+1)= 5
(x+2)= 6
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check your answer
3*15 = 8*5 + 5
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