SOLUTION: Find three consecutive integers such that twice the least integer is 12 more than the greatest integer. Thanks for your help!

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Question 351065: Find three consecutive integers such that twice the least integer is 12 more than the greatest integer. Thanks for your help!
Answer by nyc_function(2741)   (Show Source): You can put this solution on YOUR website!
2x = (x + 2) + 12

Can you finish?

HINT: The three consecutive integers are x, x + 1 and x + 2 but you need to

find x first.

Undersand?

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