SOLUTION: how do i find the sum of the numbers 2 + 4 + 6 +....+ 96 + 98 without adding each number up individually?

Algebra.Com
Question 346329: how do i find the sum of the numbers 2 + 4 + 6 +....+ 96 + 98 without adding each number up individually?
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
This is an arithmetic sequence.
S[n]=n/2(a[1]+a[n]) where n is the number of terms, s=sum, a=a term of the sequence.
n=98/2=49
S=49/2(2+98)
=49/2 * 100
=4900/2
=2450
.
Ed

RELATED QUESTIONS

Refer to the data set of body temperatures in degrees Fahrenheit given in the... (answered by ikleyn)
3. Sometimes, we can take a weighted approach to calculating the mean. Take our example... (answered by venugopalramana)
I need to find the sum of 2+4+6+8+10+...+1020. I know I'm adding 2 to each number but... (answered by ewatrrr)
1. I need three measures of central tendency—the mean, the median, and the mode—are more... (answered by Edwin McCravy)
the sum of 4 numbers got by aDDING,SUBTRACTING,DIVIDING AND MULTIPLYING 2 NUMBERS IS 441. (answered by J2R2R)
Hi, I have a question The product of 2 numbers is 96. One number is 4 more than the... (answered by Cromlix,Fombitz)
How would you set this up? The second of three numbers is 6 times the first. The third is (answered by TimothyLamb)
Explain how complex numbers combine under the following operations: a. Addition... (answered by lynnlo)
Is there a short way to do the SUM of a sequence of sums: (1) + (1+2) + (1+2+3) +... (answered by solver91311)