SOLUTION: Find three consecutive even integers such that four times the first minus the third is six more than twice the second. (My work)x, x+2, x+4 represent the three consecutive even in

Question 344261: Find three consecutive even integers such that four times the first minus the third is six more than twice the second.
(My work)x, x+2, x+4 represent the three consecutive even integers.
Such that 4times the first (4x)
Minus the third (4x-x+4)
Is 6 more than twice the second (6+2(x+2)
So...I've got 4x-x+4=2(x+2)+6
I've gone over and over this and this is the only thing I can come up with.
Thank you for your help!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find three consecutive even integers such that four times the first minus the third is six more than twice the second.
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Note: Even numbers are always a multiple of 2.
You must represent them as multiples of 2.
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1st: 2x
2nd: 2x+2
3rd: 2x+4
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Equation:
4(2x)-(2x+4) = 2(2x+2)+6
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6x-4 = 4x+10
2x = 14
x = 7
----
1st: 2x = 14
2nd: 2x+2 = 16
3rd: 2x+4 = 18
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Cheers,
Stan H.
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