SOLUTION: Find three consecutive odd integers such that the sum of the first and twice the second is equal to 15 more than twice the third.

Question 339697: Find three consecutive odd integers such that the sum of the first and twice the second is equal to 15 more than twice the third.
Found 2 solutions by josmiceli, mananth:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Call the smallest integer
The 3 integers are , , and
given:

The consecutive odd integers are 19, 21, 23
check:

OK
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
x, x+2 , x+4 be the odd integers
x+2(x+1) = 2(x+4)+15
x+2x+2 = 2x+8 +15
3x+2 = 2x+23
3x-2x=23-2
x=21
..
21,23,25

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