The largest of the 10 odd positive integers will as large as possible if all the other 9 are as small as possible. So if we make the other 9 odd integers all 1's, they will have sum 9 and that will make the 10th integer have to be 22-9 or 13. 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 13 = 22 Edwin