SOLUTION: The sum of the positive odd integers less than 50 is subtracted from the sum of the positive even integers less than or equal to 50. What is the resulting difference?

SOLUTION: The sum of the positive odd integers less than 50 is subtracted from the sum of the positive even integers less than or equal to 50. What is the resulting difference?

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Question 337088: The sum of the positive odd integers less than 50 is subtracted from the sum of the positive even integers less than or equal to 50. What is the resulting difference?
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
(2+4+6+...+48+50)-(1+3+5+...+47+49)=(2-1)+(4-3)+(6-5)+...+(48-47)+(50-48)
(2+4+6+...+48+50)-(1+3+5+...+47+49)=(1)+(1)+(1)+...+(1)+(1)<--- 25 pairs
(2+4+6+...+48+50)-(1+3+5+...+47+49)=25

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