SOLUTION: the sum of the squares of two consecutive odd postive integers is 130. find the integers

Question 335892: the sum of the squares of two consecutive odd postive integers is 130. find the integers

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
the sum of the squares of two consecutive odd positive integers is 130.
find the integers
:
Two consecutive odd integers, x and (x+2)
:
x^2 + (x+2)^2 = 130
FOIL (x+2)(x+2)
x^2 + x^2 + 4x + 4 = 130
Forms a quadratic equation
2x^2 + 4x + 4 - 130 = 0
2x^2 + 4x - 126 = 0
Factors to:
(2x + 18)(x - 7) = 0
The positive solution is all we want here
x = 7, 9 are the two consecutive odd positive integers
:
7^2 + 9^2 = 130

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