SOLUTION: The product of two consecutive integers is 4 less than four times their sum. Find the integers.I had tried to solve it but it made me just get more confused with the whole question
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-> SOLUTION: The product of two consecutive integers is 4 less than four times their sum. Find the integers.I had tried to solve it but it made me just get more confused with the whole question
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Question 333482: The product of two consecutive integers is 4 less than four times their sum. Find the integers.I had tried to solve it but it made me just get more confused with the whole question. Answer by jrfrunner(365) (Show Source):
You can put this solution on YOUR website! A. two consecutive integers : x and x+1
B. The product of two consecutive integers x*(x+1)
C. 4 less than four times their sum: 4[x+(x+1)]-4
D. x*(x+1)=4[x+(x+1)]-4 (equate the sides)
E. x^2+x=4(2x+1)-4 (simplify the equation)
F. x^2 +x=8x+4-4=8x (simplify the equation)
G. x^2=-x+8x=7x (subtract x from both sides)
H. x=7 (divide both sides by x)
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check solution by substituting x=7 back in original equation
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x*(x+1)=4[x+(x+1)]-4
7*(7+1)=4*(7+(7+1))-4
7*8=4*(15)-4
56=60-4=56
