SOLUTION: Solve using the five-step problem-solving process. An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launc

Question 323597: Solve using the five-step problem-solving process.
An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 200 meters tall. If the initial speed is 30 meters per second, how high above the ground will the pebble be after 4 seconds? Round results to the nearest tenth of a meter. please help me
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
An object's altitude, in meters, is given by the polynomial h = vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 200 meters tall. If the initial speed is 30 meters per second, how high above the ground will the pebble be after 4 seconds?
----------------
Equation:
s(t) = -9.8t^2 + vt + h
---
s(4) = -9.8(4)^2 + 30*4 + 200
---
s(4) = 163.2 meters
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Cheers,
Stan H.
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