SOLUTION: find two conseutive odd possitive odd no. whish are such that the square of their sum exceeds the sum of their square by 126

Question 321970: find two conseutive odd possitive odd no. whish are such that the square of their sum exceeds the sum of their square by 126
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the numbers be x & x+2
the sum of their squares = x^2 + (x+2)^2
the square of their sum = (x+x+2)^2
(2x+2)^2=x^2+(x+2)^2+126
4x^2+8x+4=x^2+x^2+4x+4 +126
2x^2+4x-126=0
x^2+2x-63=0
x^2+9x-7x-63=0
x(x+9)-7(x+9)=0
(x-7)(x+9)=0
x=7 OR x=-9
7 & 9
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