SOLUTION: find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer

SOLUTION: find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer

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Question 315365: find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the first integer be x
second = x+2
third = x+4
..
(x+2)(x+4)=10x+20
x^2+6x+8=10x+20
x^2-4x-12=0
x^2-6x+4x-12=0
x(x-6)+4(x-3)=0
(x-6)(x+4)=0
x= 6
the numbers are 6,8,10.

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