SOLUTION: Ten consecutive integers are arranged in order from least to greatest. If the sum of the first five integers is 200, what is the sum of the last five integers ?
Algebra.Com
Question 313618: Ten consecutive integers are arranged in order from least to greatest. If the sum of the first five integers is 200, what is the sum of the last five integers ?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
X+X+1+X+2+X+3+X+4=200
5X+10=200
5X=200-10
5X=190
X=190/5
X=38 ANS. FOR THE FIRST INTEGER.
38+1=39 ANS. THE SECOND INTEGER.
38+2=40 ANS. FOR THE THIRD INTEGER.
38+3=41 ANS. FOR THE FOURTH INTEGER.
38+4=42 ANS. FOR THE FIFTH INTEGER.
43+44+45+46+47=225 ANS. FOR THE SUM OF THE NEXT FIVE INTEGERS.
RELATED QUESTIONS
Ten consecutive integers are arranged in order from least to greatest. If the sum of the... (answered by richard1234)
Twelve consecutive integers are arranged in order from least to greatest. If the sum of... (answered by chessace,bucky)
What are five consecutive odd integers from least to greatest in which the sum of the... (answered by oberobic)
Find the integers. Write them in numerical order from least to greatest, separated with... (answered by stanbon)
What is the greatest of five consecutive integers if the sum of the integers equals... (answered by checkley77)
What is the greatest of five consecutive integers if the sum of these integers equals... (answered by stanbon)
The sum of three consecutive even integers is the same as twice the smallest of these... (answered by stanbon)
The sum of five consecutive even integers is −20. Find the integers. List them in... (answered by ikleyn)
Five times the greatest of three consecutive even integers is equal to twice the sum of... (answered by elima)